求助:控制芯片在次级,电源怎么启动?
这个是电路图,我看不明白启动电路。
原文就这么一点文字描述。Start-up circuit
As already mentioned in the introduction section, the controller is located on the secondary side of the power
transformer, and for this reason, a start-up circuit has to be provided for a correct system activation.
The start-up circuit is based on a diac sending a train of controlled pulses to the low side drive section; the floating
drive section is energised by the second secondary gate driv e transformer winding .
As soon as the L5991a wakes-up, it generates a pwm signal enabling the start-up circuit.
启动电路
由于已经在引言部分提到,位于电源的二次侧控制器变压器,因为这个原因,启动电路必须提供正确的系统激活。
发送DIAC 低侧驱动部分 列车的控制脉冲启动电路是基于浮动
驱动部分由第二栅极驱动变压器绕组通电。一旦作为L5991a唤醒的,它会产生一个PWM信号,使启动电路。
这样分析对不对:开机后,当C25电压充到32V时,DB3导通,电压加到驱动绕组上,相互耦合,上管也感应出电压,此时上下管导通。此时传递能量到次级。延迟零点几uS(R20C28的时间常数为2.5uS0后,C28充电试三极管T3导通,驱动线圈无电压,上下管截止。如果一次启动的能量不够,延迟几个mS(R16C25的时间常数36mS),DB3再次导通。
电路正常后,DB3是会周期导通。如果导通时间刚好是开关管截止时间,会短时间把开关管再次导通,对电路还是有点影响。