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變壓器最大飽和磁通計算,請各位進來大蚊進來討論......

now, I am calculation saturation valume in flyback circuit, to inspection the trasformer if work on safety area,
calculaion formula:
Bmax=Vp*10^8/k*f*Np*Ae
Vp=90VAC k=4.44  f=main switching frequeny
Np=primary turns Ae=active area of core
please give me some advice if have any other
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2004-07-13 22:13
拼命頂!!!!!!!!!!!!!!!!!!ㄐ!!!!!!!頂!
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劳同志
LV.7
3
2004-07-14 08:19
@電源傻子
拼命頂!!!!!!!!!!!!!!!!!!ㄐ!!!!!!!頂!
Your calculaion formula is for industrial frequency (transformers)!
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zzd1007
LV.3
4
2004-07-14 08:51
什么意思?你是算最大饱和磁痛吗?
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weal
LV.1
5
2004-07-14 10:51
@劳同志
Yourcalculaionformulaisforindustrialfrequency(transformers)!
the frequency is switching time of MOS
What is industrial frequency??
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weal
LV.1
6
2004-07-14 10:58
@zzd1007
什么意思?你是算最大饱和磁痛吗?
no!!
I am calculation the saturation in fact application!!
to confirm designing for trasformer(core application situation) !!
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劳同志
LV.7
7
2004-07-15 07:08
@weal
thefrequencyisswitchingtimeofMOSWhatisindustrialfrequency??
industrial frequency ---f=50-60hz;
4.44=2^0.5*pi---means the voltage wave is sine.
(pi=3.14159...)
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gwwater
LV.6
8
2004-07-15 08:47
@weal
no!!Iamcalculationthesaturationinfactapplication!!toconfirmdesigningfortrasformer(coreapplicationsituation)!!
This formular is suitable for the discontinueous mode flyback converter. because the Bmax in your formular is actually the B swing(Delta B). for continueous mode should use another formular:
Bmax=Ipeak*L/(N*Ae)
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子木
LV.1
9
2004-07-15 12:01
@gwwater
Thisformularissuitableforthediscontinueousmodeflybackconverter.becausetheBmaxinyourformularisactuallytheBswing(DeltaB).forcontinueousmodeshoulduseanotherformular:Bmax=Ipeak*L/(N*Ae)
你应该用这个公式:Bmax>LpIp/NpAe,  各个参数代表的是什么应该不用啰嗦了!
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weal
LV.1
10
2004-07-15 15:27
@劳同志
industrialfrequency---f=50-60hz;4.44=2^0.5*pi---meansthevoltagewaveissine.(pi=3.14159...)
we are use the 65KHZ switching time for MOS!!!
what are you according to this!! (use industrial frequency)
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2004-07-15 18:30
It's wrong
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wwwwwyyyr
LV.7
12
2004-07-15 20:31
My idea is: Bmax=Lp*Ip/N*Ae
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weal
LV.1
13
2004-07-16 08:14
@sometimes
It'swrong
WHY!!
please make correct answer!!!
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chong
LV.5
14
2004-07-16 11:33
@weal
weareusethe65KHZswitchingtimeforMOS!!!whatareyouaccordingtothis!!(useindustrialfrequency)
You are wrong! your formula is suitable for all transformers supplied with  sine-wave voltage, such as power distribution transformers.
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劳同志
LV.7
15
2004-07-18 07:47
@weal
WHY!!pleasemakecorrectanswer!!!
The Volt-Second Product in a coil is equal to its flux linkage:
∫v(t)*dt=ψ=N*Φ=N*B*Ac
In this case,the voltage v(t) is a constant Vi :
∴ N*B*Ac=Vi*d*T
there, d---duty cycle on a period T.
When the converter is operating on its full load or suffering some over load,
   N*Bm*Ac=Vimin*dmax*T= Vimin*Tonmax.
∴ Bm=Vimin*dmax*T= Vimin*Tonmax/N*Ac

jockey_lee: /100[第9帖] and wwwwwyyyr: /100 [第12帖] 's answer are right.
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weal
LV.1
16
2004-07-19 11:22
@劳同志
TheVolt-SecondProductinacoilisequaltoitsfluxlinkage:∫v(t)*dt=ψ=N*Φ=N*B*AcInthiscase,thevoltagev(t)isaconstantVi:∴N*B*Ac=Vi*d*Tthere,d---dutycycleonaperiodT.Whentheconverterisoperatingonitsfullloadorsufferingsomeoverload,  N*Bm*Ac=Vimin*dmax*T=Vimin*Tonmax.∴Bm=Vimin*dmax*T=Vimin*Tonmax/N*Acjockey_lee:/100[第9帖]andwwwwwyyyr:/100[第12帖]'sanswerareright.
THANKS!!!
THANKS FOR ALL FRIENDS TO JOIN THIS DISCUSS!!!
LET ME MAKE MORE CLEAR!!!
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